The game "Drunkard" became widespread in the territory of the former Soviet Union. Due to its simplicity, this card game is especially popular among children and pensioners. But before you start the fun, you should familiarize yourself in detail with its rules and features.

Rules of a card game for two

The essence of the game is that the loser is left without cards, like a drunkard who loses all his property. Cards can be dealt to two or more players. In the first case, it is better to use the smallest deck so that the game does not last too long. Before starting, participants need to agree on which card has higher value. For example, some players believe that an ace is inferior to a six.

The card game "Drunkard" is very popular among children.

In the game "Drunkard" follow the instructions:

1. Shuffle and distribute the same number of cards between players so that their value is not visible.
2. The first player takes a card from his personal deck and places it face up. The others repeat his actions. The one whose card has highest value, takes all the winnings for himself.
3. The player to the left of the previous one starts a new circle.
4. The player who runs out of cards is eliminated. This continues until a winner is determined.

If there are cards with the same value on the table, then two more cards should be placed on them, the first of which should be upside down. The one with the largest third card wins the circle.

Another version of the game: who wins

The standard "Drunkard" assumes that the winner is determined by chance. This rule often makes the game boring. For people who like to think logically, “Tactical Drunkard” is suitable.

If you want to know how to play Tactical Drunkard, use the algorithm:

1. Shuffle and distribute an equal number of cards to all players.
2. Each player takes his cards, arranges them as he sees fit and turns them face down.
3. All players place one card on the table, and the one whose card has the highest value takes the winnings.
4. The winnings do not participate in the game, but remain in the player’s piggy bank.
5. The game continues until all the cards are in the piggy bank.
6. The owner of the largest piggy bank wins.

It should be noted that if controversial point you just need to remove the cards from the game.

If you are in good company and have a deck of cards, then be sure to try playing The Drunkard. It doesn’t matter at all who wins, chance or tactics. After all, the main thing is to enjoy the game process.

Story

The origin of the game is not known with certainty. Most likely it was played for the first time on the territory of the USSR. unusual name the game received thanks simple rules, and a completely unpredictable result.

Rules

The game uses a deck of 36, 52 or 54 cards. The game can be played by two to eight players. The deck is distributed equally among all players. Players do not look at their cards (as in the game "Fool"), but place them in a pile next to them. The first player to move removes the top card from his pile and places it in the center of the table in open form. Other players in the circle do the same. The player whose card turned out to be older than all the others removes his and the “defeated” cards and puts them in another pile (option: at the bottom of his pile); order of folding cards into different options The game can be subject to certain rules or be arbitrary, which allows you to pursue one or another strategy with the goal of capturing the highest possible cards from your opponent.

A player who loses all his cards is eliminated from the game.

The winner is the player who has the entire deck in his stack. A game of giveaway is also possible, in which the one who gets rid of his cards before the others wins.

Dispute

If two or more players have the same cards (this situation is called a “dispute”), then each of these players puts one more card on top, and the one whose card turned out to be higher than all the others removes the cards. Option - each “arguing” player lays out two cards, one face down (“pawn”), and one open, which determines who takes the cards on the line.

Six

In this game, the six is ​​higher than the ace, but lower than all other cards. If this rule is not followed, the game may not end at all; cards will continue to pass from one player to another, and back.

When playing with a deck of 52 cards, this role is played by the deuce; when playing with 54 cards, by the joker.

Links

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IN Lately I play the card game Drunkard a lot with my 5 year old son. Both he and I are happy when we win, and sad when we lose.

At some point I wondered: what is the “financial” value of each of the cards in The Drunkard? Since Six beats Ace (see version of the rules under the cut), the value system in “The Drunkard” is cyclical, and the answer is not obvious. For example, is a Seven more valuable than a Six? Seven beats Six - that means yes! But on the other hand, each of them beats only one other card in the game (Seven beats Six, and Six beats Ace) - does that mean they are equal in value? But an Ace beaten by a Six is ​​in itself much more valuable than a Six beaten by a Seven - does that mean the Six is ​​more valuable?!

I decided to let you down mathematical model under the analysis of the value of cards in “The Drunkard”. The results were most unexpected.

First, here are the rules for our version of this game:

• The game involves 2 players.
• 36 cards (from sixes to aces) are dealt equally.
• Each player removes the top card of his deck and places it face up - a “battle” occurs. The winning player places all battle cards on the bottom of his deck.
• The winner of the battle is determined by the usual rank of cards (from top to bottom): Ace, King, Queen, Jack, Ten, Nine, Eight, Seven, Six. There is only one very important exception: Six beats Ace.
• If identical cards (for example, two tens) are involved in the battle, then a “dispute” occurs: another card is placed face down on top of the “arguing” cards (they are passive hostages of the dispute), and then two more cards are placed face up, which enter the battle. The winner takes all the cards in the dispute.

As is clear from the rules, victory in this game depends solely on luck - the winner is determined by the distribution of cards, since nothing depends on the players at all.

So how can we determine the "value" of a card in Drunkard? I decided to determine the value of a card in terms of the expected number of cards this card will bring if the game continues indefinitely.

Let's start with a simple task: determining the expected number of cards for only the Six and only one battle. There are 36 cards in the deck, which means that if we play Six, it enters into battle with another (randomly selected) card from the remaining 35. What can happen? There is a 4/35 chance of getting an Ace, and then we will get both a Six and an Ace. There is a 3/35 chance that another Six will be rolled, and there will be a dispute - and since we are assuming a completely random layout, we are equally likely to either win or lose it, which means that on average we are expected to keep our Six . In all other cases we lose six. Total, the expected number of cards for the Six after one battle: 7/35 Six + 4/35 Ace.

Now, let’s fill out the matrix for the expected number of all cards for one battle (the Six row is the expected number of cards received after one battle with the participation of our Six).

	Six	Seven	Eight	Nine	Ten	Jack	Lady	King	Ace
Six	7/35	0	0	0	0	0	0	0	4/35
Seven	4/35	7/35	0	0	0	0	0	0	0
Eight	4/35	4/35	11/35	0	0	0	0	0	0
Nine	4/35	4/35	4/35	15/35	0	0	0	0	0
Ten	4/35	4/35	4/35	4/35	19/35	0	0	0	0
Jack	4/35	4/35	4/35	4/35	4/35	23/35	0	0	0
Lady	4/35	4/35	4/35	4/35	4/35	4/35	27/35	0	0
King	4/35	4/35	4/35	4/35	4/35	4/35	4/35	31/35	0
Ace	0	4/35	4/35	4/35	4/35	4/35	4/35	4/35	31/35

Obviously, taking into account one battle is not enough to determine the value of a card. For example, a Six has a chance to win an Ace, which will play at some point in the future and in turn has a chance to win other cards. How to get a similar matrix, but with the expected number of cards after two battles? The answer turns out to be amazingly simple - you just need to multiply this matrix by itself! (Basics of matrix multiplication: to obtain the element (X, Y) of the multiplication result, you need to scalarly multiply the X row of the first matrix by the Y column of the second, that is, multiply the corresponding elements of these two vectors in pairs and add the results).

For example, the probability of starting with a Six and after 2 battles holding a Six is ​​(7/35)^2, since an Ace, potentially won in the first battle, does not in any way increase the chances of getting a Six in the second. However, the same Ace increases the chances of getting each of the other cards in the second battle - but the expected number of cards for the Ace in the second battle is multiplied by the probability of getting an Ace in the first battle (4/35). Etc.

Here one can quite reasonably argue that by the time of the second battle the probabilities will no longer be the same as at the time of the first, since we assume certain results of the first battle. Indeed, ideally we would have calculated all the paths of this garden of forking paths. But this is not easy to do, so we will assume that the changing probabilities are the same for all cards and the errors are somehow averaged out.

So, just a little bit of code:

Require "matrix" # Matrix of expected numbers for one battle m1 = Matrix[ , , , , , , , , ] # Matrix of expected numbers after 1000 battles (m1 to the power of 1000) m1000 = m1 ** 1000 # (values rounded) => Matrix[, , , , , , , , ]
Notice how after a certain number of battles all the expected number of cards for one map become the same - since (due to the circular value system) in the end we can win All cards, then the expected numbers for all cards converge to one number. Now there is very little left - we add up all the numbers in each row to find out the “value” of each of the cards (i.e., the expected number of cards after 1000 battles):

M1000.row_vectors.map (|row| row.reduce(&:+).round(3)) #
For clarity:

Unexpected findings:

• The value of the Six lies between the Jack and the Queen!
• Only the King and Ace have an expected final number of cards greater than 1 (that is, a positive ROI is expected).

How to play a drunkard is an interesting question for many. Origin card game under the name “Drunkard” is unknown, its name is not particularly attractive, but despite this it is very popular. When two players are involved in the game, a deck of fifty-two cards is used, and if four people are playing, a standard deck of thirty-six cards should be used.

How to play a drunkard: rules of the game

When playing, each card has a certain seniority - 2, 3, 4, 5, ... B, D, K, T. the main objective games - take other players' cards and collect the entire deck. The rules of the game are as follows.

Initially, you should choose who will be dealing the cards. This is done by drawing lots. The dealer shuffles the deck and distributes it equally among all participating players. Players who receive cards do not look at them, but place them next to them in a stack with their backs facing up (without showing the suit or value of the cards).

Following the rules of the drunkard game, the first move is made by the one who dealt the cards. The dealer removes the top card from his pile and places it face up in front of him. Following him, clockwise, other players must do the same.

As a result, whose card turns out to be higher, he takes all the open cards, placing them in the same order under his pile. In the event that two or more players have an equal number of cards, each of them must lay out one more card until it is revealed who will take all the cards.

If the last cards held by the players have same value, they are taken by the person who first puts down the card. Turn then moves to the next player clockwise. When a player is left empty-handed, he is eliminated.

The winner is the one who understands how to play the drunkard and manages to collect the entire deck.

Instructions

Draw lots and choose a donor. You can cast lots in any way - using a counting rhyme, throwing a coin up, holding an object in your fist, etc. Seat the players so that the clockwise direction can be clearly determined. It is best to sit around the table. However, the table can also be conventional - a rug on the beach or a napkin in a train compartment. If there are only two players, you can remove sixes from a deck of 36 cards. For big company A deck of 52 cards is more suitable.

If the lot has fallen to you to deal the deck, shuffle the cards well, move the deck and deal all the cards to the players. Cards must be dealt clockwise, starting from the player sitting to the left of the dealer. Players must stack the cards without turning them over.

Determine the seniority of the cards. It's ordinary. The highest is an ace, then a king, a queen, a jack, a ten, and so on until a six or two. In some variations of the game, a deuce or six beats an ace, but in relation to the other cards they are the lowest. This point needs to be discussed in advance. There are no trump cards in this game.

The dealer begins the circle. Without looking, he takes the top card, turns it over and places it in the middle of the table. The next players do the same. The bribe is taken by the one whose card turns out to be higher than the others. He must place the cards face down at the bottom of his pile, without shuffling them.

It may happen that two or even three cards of the same value turn out to be tricks. In this case, players with identical cards are given the right to play one more card. The one whose second card is higher takes the bribe. This is considered very lucky because the winner's pile of that circle is increased by one more card.

It may also happen that the players have cards of the same value last. In this case, the bribe is taken by the one who put down his card earlier, that is, the player sitting closer to the dealer, if viewed clockwise.

The game continues until one of the players runs out of cards. This participant is eliminated, the rest move on to the next round. The player sitting on the left hand from the first round deliverer. The second round is no different from the first, except for the number of players. There are options when no additional actions are taken after one participant leaves the game, the circle simply continues further. The game continues until one of the participants collects all the cards. After this, the “drunkard” can be started again, returning all players to the circle.

Helpful advice

There are also computer version this game. The rules are similar to those for regular game.

Black Jack is one of the most popular and famous card games in the world. Its rules are simple and clear, and in terms of excitement it is not inferior to poker.

You will need

• - cards

Instructions

If the game takes place in a casino, then players place bets on the boxes. There can be from one to three players on one box. Makes all decisions. Each player's bet on the box must not be less than the minimum, and the total bet of the players must not exceed the table maximum. Each player can play on any number of boxes.

At the beginning of the game, the dealer deals two cards to the players and one to himself. The player can stop or continue drawing cards. After all players have made a decision, the dealer draws cards for himself. The dealer is obliged to take a card up to 16 points inclusive, and stop at 17 or more cards. Based on the result of the set of cards, the dealer determines who won and pays or takes the bets. If the dealer and the player have the same amount of points, then the bet neither loses nor wins.